I am learning Kubernetes Label Selector at the URL below.
https://kubernetes.io/docs/concepts/overview/working-with-objects/labels/
Set-based label requirements allow filtering keys according to a set of values. Three kinds of operators are supported: in, notin and exists (only the key identifier). For example:
! partition
The fourth(This) example selects all resources without a label with key partition; no values are checked.
My assumption is that if I specify "!test", all pods will be output, I think that nothing is output when "!app" is specified.
I want to exclude the key and output as in the example described here, but the expected result was not obtained.
My @ Pc: ~ / Understanding-K8s / chap04 $ kubectl get pod -l! app
My@Pc:~/Understanding-K8s/chap04$ kubectl get pod -l !app
-bash: !app: event not found
My@Pc:~/Understanding-K8s/chap04$ kubectl get pod -l "!app"
-bash: !app: event not found
My@Pc:~/Understanding-K8s/chap04$ kubectl get pod -l "!test"
-bash: !test: event not found
My@Pc:~/Understanding-K8s/chap04$ kubectl get pod -l !test
-bash: !test: event not found
The result of executing the --show-labels command is as follows.
My @ Pc: ~ / Understanding-K8s / chap04 $ kubectl get pod --show-labels
NAME READY STATUS RESTARTS AGE LABELS
nginx-pod-a 1/1 Running 0 89m app=photo-view,env=stage
nginx-pod-b 1/1 Running 0 89m app=imagetrain,env=test
nginx-pod-c 1/1 Running 0 89m app=prediction,env=test
nginx-pod-d 1/1 Running 0 89m app=photo-view,env=stage
nginx-pod-e 1/1 Running 0 89m app=imagetrain,env=stage
nginx-pod-f 1/1 Running 0 89m app=photo-view,env=prod
How can I exclude the intended keys such as app and env?
tyzbit has given me the answer, and I have tried. I couldn't describe the result well in the comment, so I will add it here.
My@Pc:~/Understanding-K8s/chap04$ kubectl get pod -l '!app'
No resources found in default namespace.
My@Pc:~/Understanding-K8s/chap04$ kubectl get pod -l '!test'
NAME READY STATUS RESTARTS AGE
nginx-pod-a 1/1 Running 0 162m
nginx-pod-b 1/1 Running 0 162m
nginx-pod-c 1/1 Running 0 162m
nginx-pod-d 1/1 Running 0 162m
nginx-pod-e 1/1 Running 0 162m
nginx-pod-f 1/1 Running 0 162m
Girdhar Singh Rathore teaches me AWK and jsonpath.
(Maybe, I've written the wrong format...)
My@Pc:~$ kubectl get pods --show-labels | awk '$6 !~/app/ {print ;}'
NAME READY STATUS RESTARTS AGE LABELS
My@Pc:~$ kubectl get pods --show-labels | awk '$6 !~/test/ {print ;}'
NAME READY STATUS RESTARTS AGE LABELS
nginx-pod-a 1/1 Running 0 18m app=photo-view,env=stage
nginx-pod-d 1/1 Running 0 18m app=photo-view,env=stage
nginx-pod-e 1/1 Running 0 18m app=imagetrain,env=stage
nginx-pod-f 1/1 Running 0 18m app=photo-view,env=prod
My@Pc:~$ kubectl get pods -o jsonpath='{range .items[*]} {.metadata.name} {.metadata.labels} {"\n"} {end}' | awk '$2 !~/app/ {print $1}'
My@Pc:~$ kubectl get pods -o jsonpath='{range .items[*]} {.metadata.name} {.metadata.labels} {"\n"} {end}' | awk '$2 !~/test/ {print $1}'
nginx-pod-a
nginx-pod-d
nginx-pod-e
nginx-pod-f
The !
is getting interpreted by your shell, use a single quote to prevent this. The correct syntax is:
kubectl get pods -l '!app'
You can use awk
kubectl get pods --show-labels | awk '$6 !~/app/ {print ;}'
or -o jsonpath
kubectl get pods -o jsonpath='{range .items[*]} {.metadata.name} {.metadata.labels} {"\n"} {end}' | awk '$2 !~/app/ {print $1}'
or selector
kubectl get pods -l '!app'