I am using kubectl in order to retrieve a list of pods:
kubectl get pods --selector=artifact=boot-example -n my-sandbox The results which I am getting are:
NAME READY STATUS RESTARTS AGE
boot-example-757c4c6d9c-kk7mg 0/1 Running 0 77m
boot-example-7dd6cd8d49-d46xs 1/1 Running 0 84m
boot-example-7dd6cd8d49-sktf8 1/1 Running 0 88mI would like to get only those pods which are "ready" (passed readinessProbe). Is there any kubectl command which returns only "ready" pods? If not kubectl command, then maybe some other way?
You can use this command:
kubectl -n your-namespace get pods -o custom-columns=NAMESPACE:metadata.namespace,POD:metadata.name,PodIP:status.podIP,READY-true:status.containerStatuses[*].ready | grep trueThis will return you the pods with containers that are "ready".
To do this without grep, you can use the following commands:
kubectl -n your-namespace get pods -o go-template='{{range $index, $element := .items}}{{range .status.containerStatuses}}{{if .ready}}{{$element.metadata.name}}{{"\n"}}{{end}}{{end}}{{end}}'
kubectl -n your-namespace get pods -o jsonpath='{range .items[*]}{.status.containerStatuses[*].ready.true}{.metadata.name}{ "\n"}{end}'
This will return you the pod names that are "ready"
You can try this command which uses jq to transform kubectl json output as you require.
kubectl get pods --all-namespaces -o json | jq -r '.items[] | select(.status.phase = "Ready" or ([ .status.conditions[] | select(.type == "Ready") ] | length ) == 1 ) | .metadata.namespace + "/" + .metadata.name'