Suppose there is a service with name "SVC", running in namespace NS in kubernetes cluster. I need to extract its IP (i.e clusterIP)

I could write some code (below), which works, but I think this approach should not be taken. As this code will be called frequently, loading config every time is a waste. How should I better do it:

namespace := "NS"
serviceName := "SVC"
clusterIP := ""

kubeconfig := filepath.Join(
     os.Getenv("HOME"), ".kube", "config",
)

config, err := clientcmd.BuildConfigFromFlags("", kubeconfig)
if err != nil {
    fmt.Println("BuildConfigFromFlags Failed")
    return string(""), err
}

clientset, err := kubernetes.NewForConfig(config)
if err != nil {
    fmt.Println("NewForConfig Failed")
    return string(""), err
}

svcList, err :=  clientset.CoreV1().Services(namespace).List(metav1.ListOptions{
    FieldSelector: "metadata.name=" + serviceName,
    })

//fmt.Printf("kubecofig: %s\n",kubeconfig)
//fmt.Printf("config: %#v", config)
//fmt.Printf("nameSpaceList: %#v", svcList)
for _, svc := range svcList.Items {
    clusterIP = svc.Spec.ClusterIP
    break
}

fmt.Printf("Service IP: %s", clusterIP)

Is there a way I can write concise code like this and get my desired result. If there is a way to use "&corev1.service" , can anybody please tell me how?