Deployment to the particular Kubernetes cluster node

5/7/2018

I am trying to implement the CI/CD pipeline using Kubernetes , Jenkins with my private SVN repository. And I am planning to use Kubernetes cluster having 3 master and 15 worker machine/Node. And Using Jenkins to deploy the microservice developed using spring boot. So When I am deploying using Jenkins , How I can define which microservice need to deploy in which node in kubernetes cluster?. Do I need to specify in Pod ? Or Any other definition ?

-- Jacob
jenkins
kubernetes

2 Answers

5/7/2018

How I can define which microservice need to deploy in which node in kubernetes cluster?. Do I need to specify in Pod ? Or Any other definition ?

  • As said in other answers you don't need to do this, but you can if there is any reason to do so using deprecated nodeSelector or preferable affinities. They are well worth the time to read since you can have some pods relating to specific services/microservices group together or away from each other across available nodes to allow for more flexible and resilient architecture and proper spread out. This way you are helping scheduler deciding where to place what to achieve desired layout. For most basic needs previously mentioned resource allocation can do the trick but for any fine graining you have affinity (and anti affinity) at your disposal. Documentation detailing this is here: https://kubernetes.io/docs/concepts/configuration/assign-pod-node/
-- Const
Source: StackOverflow

5/7/2018

Kubernetes figures out what nodes should run what pods. You don't have to do that. You have to indicate how much memory and cpu each pod needs, k8s to a first approximation figures out the rest.

That said, what you do have to do is figure out how to partition the full set of workloads you need to run- say, by environment (dev/stage/prod), or by tenant (team X/team Y/team Z or client X/client Y/client Z)- into namespaces, then figure out what workflow makes sense for that partitioning, then configure the CI to satisfy that workflow.

-- Jonah Benton
Source: StackOverflow